Private/Get-FileName.ps1
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<# .SYNOPSIS Get a file from GUI. .DESCRIPTION Show a windows form to select the input file Return the filename text with full path. .PARAMETER initialDirectory The file selection window shows in initial directory. .EXAMPLE Get-FileName -initialDirectory c:\temp The file selection window would start at c:\temp. #> Function Get-FileName { [CmdletBinding()] Param( [string]$initialDirectory = '.' ) $null = Add-Type -AssemblyName System.windows.forms $OpenFileDialog = New-Object -TypeName System.Windows.Forms.OpenFileDialog $OpenFileDialog.initialDirectory = $initialDirectory $OpenFileDialog.filter = 'CSV (*.csv)| *.csv' $null = $OpenFileDialog.ShowDialog() return $OpenFileDialog.filename } |